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Mount path to Mount path Data Migration

  • 16 June 2022
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I need to check if there is any option to move the data from one mount path to another mount path in the same library. I need this to be done for mitigating over commit issue at back end storage. I am having 3-4 mount paths in which only one job is there , i want to move that one job to any other MP within the library and get that deleted so that over commit issue will get solved. 

 

Current Version: V11 SP26.23

Backend Storage : Netapp

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Best answer by YYZ 16 June 2022, 18:17

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Userlevel 5
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Hello @Saimanoj 

There is no way to move data from one mount path to an existing mount path, but if you want to move it to a new share you can use the Move Mount Path operation.

https://documentation.commvault.com/11.26/expert/9302_moving_mount_path.html

A way to “pseudo-move” existing data to existing mount paths is to disable the mount path you want to remove for new data. This will have subsequent jobs re-baseline the existing data on the remaining mount paths while allowing backups to age according to storage policy retention.

You may also want to prevent block references to speed up the process.

https://documentation.commvault.com/11.26/expert/9376_disabling_write_operations_on_mount_path.html

Userlevel 4
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This is a long post - but should have the answer - its worth a full read

 

Towards the end you should see a write up that could address your issue

I've extracted it in italics below

 

 

So … I misunderstood the instructions for Moving a Mount Path which say:

  • The move mount path operation overwrites the destination mount path. Therefore, ensure that the destination mount path is an empty folder.

I mistakenly thought this meant I couldn’t move to one of the existing drives but it turns out that all I needed was to create a new folder.  I created L:\MP4 and was able to move everything off M: to that new folder so I’m in a good position to change the configuration on the M: drive.  Thanks everyone.  @YYZ was correct and I’ll mark their reply as the solution.

Ken

 

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